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Q.

In a hypothetical Bohr hydrogen atom, the mass of the electron is doubled. The energy E0 and radius r0 of the first orbit will be: (a0 is the Bohr radius)

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a

E0 = –27.2 eV; r0 = a0/2

b

E0 = –13.6eV; r0 =a0

c

E0 = –27.2 eV; r0 = a0

d

E0 = –13.6eV; r0 = a0/2

answer is C.

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Detailed Solution

As we know

rn=h24π2kZme2, En=2π2k2e4mZ2h2n2

So if the mass of the electron is doubled the  radius will be halved and energy will be doubled.

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