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Q.

In a hypothetical Bohr’s hydrogen atom the mass of the electron is doubled. The energy E0 and radius r0 of the first orbit will be ( a0 is the Bohr radius for the first orbit)

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a

E0=−27.2 eV, r0=a0

b

E0=−13.6 eV, r0=a0/2

c

E0=−27.2 eV, r0=a0/2

d

E0=−13.6 eV, r0=a0

answer is C.

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Detailed Solution

E∝me  and r∝1me  when mass of electron is doubled, then  E→2E0 and  r→a02

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