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Q.

In a II order reaction, when the concentration of both the reactants are equal, the reaction is completed 20% in 500 sec. How long (in seconds) it would take for the reaction to go to 60% completion?

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answer is 3000.

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Detailed Solution

According to the given condition,
10.8a=1a+K×500

10.4a=1a+K×t

0.251.5=500t

t=3000 sec

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