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Q.

In a journey of 160 km, a train covers the first 120 km at 80 km/h and the remaining at 40km/h. What will be the average speed of the whole journey?

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a

30 km/h

b

32.4 km/h

c

23 km/h

d

64 km/h

answer is C.

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Detailed Solution

Total distance =160m
$s_{1} = 120 km s_{2} = 40 km v_{1} = 80 km / h v_{2} = 40 km / h t_{1} = \frac{s_{1}}{v_{1}} = \frac{120}{80} = \frac{3}{2} hrs t_{2} = \frac{s_{2}}{v_{2}} = \frac{40}{40} = 1 hr Avg v = \frac{s_{1} + s_{2}}{t_{1} + t_{2}} = \frac{160}{\frac{3}{2} + 1} = \frac{160}{5 / 2} = \frac{160 \times 2}{5} = 64 km / h$

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