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In a junction transistor operating under common emitter connections, the base current is changed by $20 μ A$ . Due to this base-emitter voltage is changed by 0.02 volt and collector current changed by 2mA. Find the voltage gain of amplifier if load resistance $R_{L}$ is $5000 Ω$ . (Take $R_{B} = 0$ )

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100

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Detailed Solution

$β = \frac{δ I_{C}}{δ I_{B}} = \frac{2 \times 10^{- 3}}{20 \times 10^{- 6}} = 100$

Input resistance = $R_{I} = \frac{δ V_{B E}}{δ I_{B}} = \frac{0.02}{20 \times 10^{- 6}} = 1000 Ω$ ,

Voltage gain = $β \times \frac{R_{L}}{R_{I}} = 100 \times \frac{5000}{1000} = 500$

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