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Q.

In a L-R decay circuit, the initial current is I. The total charge that has flown through the resistor till the energy in the inductor has reduced to one-fourth is initial value, is LIXR.  The value of ‘X’ is

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answer is 2.

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Detailed Solution

E1=12Ll2,E2=E14⇒I′=I2le−t/ε=I2,tε=log⁡2dQ=I′dt,Q=∫0log⁡2 le−t/εdt∣=lεe−t/ε0log2=∣ε1−elog⁡1/2=lε2=IL2R,X=2

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