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Q.

In a long jump competition there are 15 participants  P1,P2,.......,P15 from different schools. They have to perform their jumps in a random order given by the event referee. In the given order if  P1 has to jump before  P5, then the probability that  P2 has to jump immediately after  P1 is equal to  1K,(KN) then sum of the digits of  'K' equals 

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answer is 6.

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Detailed Solution

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E:P1 has to jump before  P5
F:P2  has to jump immediately after  P1
P(FE)=P(FE)P(E),  where  P(E)= 15C2 15P2=12 and  P(FE)= 14C2 15P3=130
    P(FE)=115,  sum of its digits = 6

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