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Q.

In a lottery with 30 tickets numbered 1 to 30, two tickets are drawn simultaneously. The probability that
atleast one of the two tickets drawn is not a prime number is :

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a

$\frac{26}{29}$

b

$\frac{25}{29}$

c

$\frac{5}{29}$

d

$\frac{3}{29}$

answer is D.

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Detailed Solution

No of cases that two numbers are prime numbers $=^{10} C_{2}$

Total possible cases $=^{30} C_{2}$

Required Probability $= 1 - \frac{10 \times 9}{30 \times 29}$

$= \frac{26}{29}$

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In a lottery with 30 tickets numbered 1 to 30, two tickets are drawn simultaneously. The probability thatatleast one of the two tickets drawn is not a prime number is :