In a “magic square”, the sum of the numbers in each row, in each column and along the diagonals is the same. Is this a magic square?

Along the first row: $\frac{4}{11}+\frac{9}{11}+\frac{2}{11}=\frac{15}{11}$

Along the second row: $\frac{3}{11}+\frac{5}{11}+\frac{7}{11}=\frac{15}{11}$

Along the third row: $\frac{8}{11}+\frac{1}{11}+\frac{6}{11}=\frac{15}{11}$

Along the first column: $\frac{4}{11}+\frac{3}{11}+\frac{8}{11}=\frac{15}{11}$

Along the second column: $\frac{9}{11}+\frac{5}{11}+\frac{1}{11}=\frac{15}{11}$

Along the third column: $\frac{2}{11}+\frac{7}{11}+\frac{6}{11}=\frac{15}{11}$

Along the first diagonal: $\frac{4}{11}+\frac{5}{11}+\frac{6}{11}=\frac{15}{11}$

Along the second diagonal: $\frac{8}{11}+\frac{5}{11}+\frac{2}{11}=\frac{15}{11}$

Yes, it is a magic square as the sum of numbers in each row, column and diagonal is same.