In a magnetic field of 0.05T, area of a coil changes from 101 cm2 to 100 cm2 without changing the resistance which is 2 Ω . The amount of charge that flow during this period is

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In a magnetic field of 0.05T, area of a coil changes from $101 {cm}^{2} to 100 {cm}^{2}$ without changing the resistance which is $2 Ω$ . The amount of charge that flow during this period is

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10^{- 6} C

8 \times 10^{- 6} C

2 \times 10^{- 6} C

2.5 \times 10^{- 6} C

answer is A.

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Detailed Solution

q = \frac{d ϕ}{R}; q = \frac{B (A_{2} - A_{1})}{R}

$q = \frac{0.05 \times 10^{- 4}}{2} = 2.5 \times 10^{- 6} C$

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