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Q.

In a medium the speed of light wave decreases to 0.2 times to its speed in free space. The ratio of relative permittivity to the refractive index of the medium is x :1. The value of x is ____.
( Given speed of light in free space =3×108ms−1 and for the given medium μr=1)

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answer is 5.

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Detailed Solution

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Refractive index of the medium is given by

μ=cv=c0.2c=5

⇒μ=μrEr

⇒ϵr=52=25   ∵μr=1

∴ϵrμr=5:1

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