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Q.

In a Mendelian dihybrid cross for seed shape and seed colour, the population has 256 plants. How many plants are heterozygous for both the traits?

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a

16

b

64

c

32

d

128

answer is B.

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Detailed Solution

The probability of double heterozygous conditions in the Mendelian dihybrid cross experiment is 4/16. Hence, in a population of 256 plants, the number of double heterozygotes is 4/16 X 256 = 64. 

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In a Mendelian dihybrid cross for seed shape and seed colour, the population has 256 plants. How many plants are heterozygous for both the traits?