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Q.

In a Mendelian dihybrid cross the number of phenotypic recombinants is 36 in F2 generation. The number of organisms with the genotype that itself accounts for 1/4th of F2 generation is

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a

18

b

48

c

12

d

24

answer is B.

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Detailed Solution

Phenotypic recombinant 6/16

Such individuals are 36 in a given cross

Total number of progeny obtained in the cross is 

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The progeny that itself accounts 1/4th of total progeny are (YyRr) – 4/16

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