In a mercury thermometer, the ice point (lower fixed point) is marked as 10° and the steam point (upper fixed point) is marked as 130°. At 40°C temperature, what will this thermometer read?

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58°

78°

66°

62°

answer is D.

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Detailed Solution

Using $\frac{T_{C} - 0}{100 - 0} = \frac{T - 10}{130 - 10}$

$\Rightarrow$ $\frac{40 - 0}{100 - 0} = \frac{T - 10}{130 - 10}$

$\Rightarrow$ $\frac{40}{100} = \frac{T - 10}{120} or \frac{2}{5} = \frac{T - 10}{120}$

$\Rightarrow$ 5T $-$ 50 = 240

$\Rightarrow$ 5T = 290 $\Rightarrow$ $T = \frac{290}{5} = 58^{o}$

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