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In a metal chloride, the mass of the metal and chlorine are in the ratio 1:2. The equivalent mass of the metal will be

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17.75

106.5

35.5

answer is D.

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Detailed Solution

W_M : W_Cl = 1:2
$\large \frac{W_{M}}{W_{Cl}}\;=\;\frac{E_M}{E_{Cl}}$
$\large \frac{1}{2}\;=\;\frac{E_M}{35.5}$
E_M = 17.75
Ew of metal = 17.75

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