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In a meter bridge experiment resistances are connected as shown in the figure. Initially resistance P=4 $Ω$ and the neutral point N is at 60 cm from A. Now an unknown resistance R is connected in series to P and the new position of the neutral point is at 80 cm from A. The value of unknown resistance R is :

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$6 Ω$

$7 Ω$

$\frac{20}{3} Ω$

$\frac{33}{5} Ω$

answer is A.

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Detailed Solution

$I n t h e f i r s t c a s e \frac{4}{x} = \frac{60}{40} i n t h e s e c o n d c a s e \frac{4 + R}{x} = \frac{80}{20}$

solving for R

R = $\frac{20}{3}$

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