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Q.

In a metre bridge, the balance is found at 40 cm point when $20 Ω$ is connected in the first arm of the bridge. Then the resistance in the second arm should be

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a

$30 Ω$

b

$200 Ω$

c

$400 Ω$

d

$100 Ω$

answer is C.

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Detailed Solution

$x = 20 Ω$

$l = 40 cm$

R=?

$\frac{x}{R} = \frac{l}{100 - l}$

$\frac{26}{R} = \frac{4}{6}$

$R = 30 Ω$

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In a metre bridge, the balance is found at 40 cm point when20 Ω is connected in the first arm of the bridge. Then the resistance in the second arm should be