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In a mixture of A and B, components show negative deviation when

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A-B interaction is weaker than A- A and B-B interaction.

A-B interaction is not related to A-A and B-B interaction.

$∆$ V_mix= 0, $∆$ S_mix >0

$∆$ V_mix >0, $∆$ S_mix = 0

answer is A.

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Detailed Solution

In a mixture component A and component B, negative Deviation is shown as,

△V_mixing<0.

i.e., For Negative Deviation, △V_mixing=-ve , △H_mixing= -ve

Because the forces of attraction between components A and B is greater.

Due to that the tendency of escaping of molecules AB from solution becomes less than that of pure liquids. A-B attractive forces is greater than A-A and B-B attractive forces.

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