In a mixture of $A$ and $B$ , components show negative deviation when

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${ΔV}_{mix} = 0, {ΔS}_{mix} = 0$

$A - B$ interaction is weaker than $A - A$ and $B - B$ interaction

${ΔV}_{mix} = 0, {ΔS}_{mix} > 0$

$A - B$ interaction is stronger than $A - A$ and $B - B$ interaction

answer is A.

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Detailed Solution

We know that a mixture shows a negative deviation when $∆ V_{mix} < 0$ .

i.e., because the forces between components A and B are greater, due to that the tendency of escaping of molecules AB from solution becomes less than that of pure liquids. It means $A - B$ interaction is stronger than $A - A$ and $B - B$ interaction.

Hence, option(a) is correct.

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