Q.

In a non-leap year, the probability of getting 53 Sundays or 53 Tuesdays or 53 Thursdays is

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a

3/7

b

1/7

c

4/7

d

2/7

answer is C.

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Detailed Solution

In a non-leap year,  there are 365 days =52 weeks and one day

one  day can be any one of the 7 days of the week

n(S)=7

E= Event of getting 53 Sundays or 53 Tuesdays or 53 Thursdays i

n(E)={sunday ,tuesday,Thursday}=3

P(E)=3/7

 

 

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