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Q.

In a normal spinel type structure, the oxide ions are arranged in ccp, whereas 1/8 tetrahedral holes are occupied by Zn2+ ions and 50% of octahedral holes are occupied by Fe3+ ions. The formula of the compound is

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a

Zn2Fe2O4

b

ZnFe2O2

c

ZnFe2O3

d

ZnFe2O4

answer is C.

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Detailed Solution

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Effective no. of O2- in a unit cell=8×18+6×12=4 Effective no. of Zn2+ ions in a unit cell=8×18=1 Effective no. of Fe3+ ions in a unit cell=4×12=2 ∴General formula is ZnFe2O4.

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