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In a p-n-p transistor circuit, the collector current is 10 mA. If 90% of the holes reach the collector, find emitter and base current.

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11.1 mA , 1.1 mA

111.1 mA , 22.2 mA

12.4mA , 11.1mA

15 mA , 11.1 mA

answer is A.

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Detailed Solution

$I_{b} = \frac{10}{90} \times 10 m A \Rightarrow 1.1 m A$

(ii) $I_{E} = I_{b} + I_{c} = 11.1 m A$

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