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In a photo electric experiment when yellow light is used stopping potential is found to be $z e r o$ . If the yellow light is replaced by blue light, then stopping potential becomes $V_{0}$ . If red light is used in the same experiment the stopping potential would be

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zero

$\frac{V_{0}}{2}$

insufficient information to find the stopping potential

$\frac{V_{0}}{4}$

answer is C.

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Detailed Solution

Energy of individual photon of red light is less than that of yellow light. So emission of photo electron will not take place.

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