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In a photoelectric effect, an em-wave is incident on a metal surface and electrons are ejected from the surface. If the work function of the metal is 2.14 eV and the stopping potential is 2V, what is the wavelength of the em-wave?
(Given hc = 1242 eV-nm where h is the Planck's constant and c is the speed of light in vacuum.)

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400 nm

600 nm

200 nm

300 nm

answer is D.

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Detailed Solution

$\begin{array}{l} eV = E - ϕ \\ 2 eV = E - 2.14 eV \\ E = 4.14 eV \\ E = \frac{hc}{λ} \\ λ = \frac{1242}{4.14} = 300 nm \end{array}$

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