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In a photoelectric effect experiment, for radiation of frequency $υ_{0}$ with ${hv}_{0} = 8 eV,$ electrons are emitted with maximum kinetic energy $2 eV$ . What is the maximum kinetic energy of the electrons emitted for incoming radiation of frequency $1.25 v_{0}$ ?

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$3.25 eV$

$1 eV$

$9.25 eV$

$4 eV$

answer is C.

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Detailed Solution

$hυ = W_{ex} + maximum kinetic energy$

${hv}_{0} = 8 eV = W_{ex} + 2 eV \Rightarrow W_{ex} = 6 eV$

For incoming radiation, energy is

$h \times 1.25 v_{0} = 10 eV, W_{ex} = 6 eV$

$∴$ Kinetic energy (maximum) = 4 eV.

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