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In a photoelectric experiment for 4000 Å incident radiation, the potential difference to stop the ejection is 2 V. If the incident light is changed to 3000 Å, then the potential required to stop the ejection of electrons will be

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2 V

Less than 2 V

Zero

Greater than 2 V

answer is D.

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Detailed Solution

According to Einstein's photoelectric equation, $E = W_{0} + K_{max}$
$\Rightarrow V_{0} = \frac{hc}{e} [\frac{1}{λ} - \frac{1}{λ_{0}}]$
Hence if $λ$ decreases V₀ increases.

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