In a photoelectric experiment for $4000 \stackrel{0}{\mathrm{A}}$ incident radiation, the potential difference to stop the ejection is 2V. If the incident light is changed to $3000 \stackrel{0}{\mathrm{A}}$, then the potential required to stop the ejection of electrons will be

According to Einstein’s photoelectric equation,

$\mathrm{E}={\mathrm{W}}_0+{\mathrm{K}}_{max}\Rightarrow {\mathrm{V}}_0=\frac{\mathrm{hc}}{\mathrm{e}}\left(\frac{1}{\mathrm{\lambda }}-\frac{1}{{\mathrm{\lambda }}_0}\right)$
So, V_o depends upon frequency and energy of incident radiation and nature of material .

Decreasing the wavelength of incident radiation, increases the stopping potential.

$\Rightarrow {\mathrm{V}}_2 > {\mathrm{V}}_1$

$\Rightarrow {\mathrm{V}}_2 > 2\mathrm{V}$