In a photoelectric experiment, kinetic energy of photoelectrons was plotted against the frequency of incident radiation (v), as shown in figure. Which of the following statements is correct?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

The threshold frequency is v₁

As the frequency of incident radiation increase kinetic energy of photoelectrons decreases

It is impossible to obtain such a graph.

The slope of this line is equal to Planck's constant.

answer is B.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The slope of the line is equal to the plank's constant

hv =hv₀ + K.E

K.E = hv - hv₀

The above equation with the equation of a straight line (y=mx+c)

so the slope of the graph between KE and v is Planck's Constant.

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test