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In a photoelectric experiment, when energy of photon of incident radiation is 6.5 eV, the stopping potential is found to be 3 V. In the same experimental set up, what will be the wave length of incident radiation, if the stopping potential is 2 V ?

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$2258 \overset{o}{A}$

$3428 \overset{o}{A}$

$3642 \overset{o}{A}$

$5240 \overset{o}{A}$

answer is A.

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Detailed Solution

Work function of target metal $= 6.5 - 3 = 3.5 eV$

When stopping potential is 2 volt, energy of each photon of incident radiation $3.5 + 2 = 5.5 eV$

Wave length of incident radiation $= \frac{12420}{5.5} \overset{o}{A} = 2258 \overset{o}{A}$

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