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In a PN junction barrier potential is 0.4V and width of depletion zone is $1 μ m$ . Then the intensity of electric field is the depletion zone is

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$4 \times 10^{5} V / m$ ; n to p region

$2 \times 10^{5} V / m$ ; p to n region

$4 \times 10^{5} V / m$ ; p to n region

$2 \times 10^{5} V / m$ ; n to p region

answer is A.

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$V = E d$

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