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Q.

In a pn junction diode, the thickness of depletion layer is 2 x 10^-6m and barrier potential is 0.3v. The Intensity of the electric field at the junction is —

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a

1.5x10⁵ v /m from p to n side

b

1.5x10⁵ v /m from n topside

c

0.6x10^-6 v /m from n to p side

d

0.6x10^-6 v /m from p to n side

answer is C.

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Detailed Solution

$E = \frac{v_{B}}{d} = \frac{0 .3}{2 \times 10^{- 6}} = 1 .5 \times 10^{5} v / m$ Always from n to p side

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