Q.

In a population in Hardy- Weinberg equilibrium 64% of the individuals show recessive trait. What is the percentage of heterozygotes in the individuals?

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a

40%

b

32%

c

20%

d

9%

answer is C.

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Detailed Solution

q2=64100=0.64

p + q = 1

q = 0.8
p = 0.2

No. of Heterozygotes 2pq=2×0.8×0.2

=0.32=32100

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