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Q.

In a population in Hardy-Weinberg equilibrium, a gene locus has two alleles 'A' and 'a'. If the frequency of dominant allele 'A' is 0.8, then what will be the frequency of homozygous dominant, heterozygous dominant and homozygous recessive individuals in the population?           

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a

0.32 (AA); 0.64 (Aa); 0.04 (aa)

b

0.36 (AA); 0.48 (Aa); 0.16 (aa)

c

0.48 (AA); 0.36 (Aa); 0.16 (aa)

d

0.64 (AA); 0.32 (Aa); 0.04 (aa)

answer is A.

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Detailed Solution

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If dominant allelic frequency is 0.8 means recessive allelic frequency is 0.2 (1-0.8 = 0.2). 

Then AA (p2) = 0.8 x 0.8 = 0.64

2Aa (2pq) = 2 (0.8 x 0.2) = 0.32

aa (q2) = 0.2 x 0.2 = 0.04.

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In a population in Hardy-Weinberg equilibrium, a gene locus has two alleles 'A' and 'a'. If the frequency of dominant allele 'A' is 0.8, then what will be the frequency of homozygous dominant, heterozygous dominant and homozygous recessive individuals in the population?