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In a population of 1,000 individuals, 600 are homozygous Rh⁺(DD), 240 are heterozygous Rh⁺(Dd) and 160 are Rh^- (dd). The frequency of recessive allele (d) in that population is

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0.32

0.56

0.16

0.28

answer is D.

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Detailed Solution

Frequency of recessive allele (q) = $\frac{2 (No . of recessive individuals) + No . of heterozygotes}{2 (Total no . of individuals)}$ = $\frac{2 (160) + 240}{2 (1000)}$ = 0.28

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