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Q.

In a population of 3,000 individuals in Hardy – Weinberg equilibrium, the frequency of dominant allele of an autosomal gene is 0.6.  The gene has only two alleles. What is the number of homozygous individuals in that population, with reference to that gene 

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a

1080

b

1560

c

1440

d

2520

answer is D.

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Detailed Solution

Homozygous individuals are p2+q2

From the given data 

Total population =3000

p = 0.6; p2 = 0.36

q = 04; q2 = 0.16

p2+q2 = 0.36+0.16 = 0.52

Number of homozygous individuals = 0.52 X 3000 = 1560

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