Q.

In a population of 3,000 individuals in Hardy – Weinberg equilibrium, the frequency of dominant allele of an autosomal gene is 0.6.  The gene has only two alleles. What is the number of homozygous individuals in that population, with reference to that gene 

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

1080

b

1560

c

1440

d

2520

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Homozygous individuals are p2+q2

From the given data 

Total population =3000

p = 0.6; p2 = 0.36

q = 04; q2 = 0.16

p2+q2 = 0.36+0.16 = 0.52

Number of homozygous individuals = 0.52 X 3000 = 1560

Watch 3-min video & get full concept clarity

hear from our champions

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon