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Q.

In a potentiometer, an auxiliary cell of 2V is connected along with a rheostat at $5 Ω$ mark. If potentiometer wire is 1000cm long and its resistance is $15 Ω$ , then balance length obtained for a cell of 1.5V is around

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a

100cm

b

1.5m

c

1000cm

d

1cm

answer is C.

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Detailed Solution

$V = (\frac{ER}{R + R_{5} + r}) \frac{l}{L}$

$1.5 = (\frac{2 \times 15}{15 + 5 + 0}) \frac{l}{1000}$

$\frac{15}{10} = \frac{2 \times 15}{20} \times \frac{l}{1000}$

$\frac{l}{1000} = 1 \Rightarrow l = 1000 cm$

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