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In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of $10 Ω$ is connected in parallel to the cell then the balancing length changes by 60cm. Find the internal resistance of a cell

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$1 Ω$

$2 Ω$

$1.2 Ω$

$2.1 Ω$

answer is C.

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Detailed Solution

$r = [\frac{l_{1} - l_{2}}{l_{2}}] R$

$= [\frac{560 - 500}{500}] 10$

$= \frac{6}{5}$

$r = 1.2 Ω$

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