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Q.

In a potentiometer wire experiment the emf of a battery in the primary circuit is 20volt and its internal resistance is 5Ω  . There is a resistance box (in series with the battery and the potentiometer wire) whose resistance can be varied from 120Ω   to 170Ω  . Resistance of the potentiometer wire is 75Ω  . The following potential difference can't be measured using this potentiometer

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a

5V

b

6V

c

7V

d

8V

answer is D.

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Detailed Solution

 V1=(205+120+75)75  andV2=(205+170+75)75
Answer lies between  V1and  V2
 

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