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Q.

 In a process, the pressure of an ideal gas is proportional to square of the volume of the gas. If the temperature of the gas increases in this process, then work done by this gas

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a

(c) is zero

b

(a) is positive

c

(b) is negative

d

(d) may be positive or negative

answer is A.

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Detailed Solution

p∝V2 

∴  TV∝V2 or  T∝V3

⇒V∝T1/3

T is increasing. So, V will also increase. Hence, work done will be positive.

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