Q.

In a radioactive decay chain reaction,  90230Th  nucleus decays into  84214Po  nucleus. The ratio of the number of  α to number of  β  particles emitted in this process is _________.

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answer is 2.

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Detailed Solution

Th90230Po84214+nα24+mβ10 
By conservation of mass, we have
230=214+4n 
 n=164=4
By conservation of charge, we have
 90=84+n×2m×1 90=84+4×2m×1 m=9290=2 nm=42=2

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