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In a radioactive decay chain, $_{90}^{232} {Th nucleus decays to}_{82}^{212} Pb nucleus. Let N_{α} and N_{β}$ be the number of $α and β^{-}$ particles, respectively, emitted in this decay process which of the following statements is (are) true?

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$N_{α} = 5$

$N_{α} = 6$

$N_{β} = 2$

$N_{β} = 4$

answer is A, C.

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Detailed Solution

Considering the laws of conservation of mass number (A) and atomic number (Z) , we can write ,

232 - $4 \times N_{α} = 212 . . . . . . . . . . . (i)$

and 90 -2 $\times N_{α} + N_{β} \times 1 = 82 . . . . . . . . . . . . (i i)$

Solving , $N_{α} = 5 a n d N_{β} = 2$

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