In a radioactive decay M_X, M_Y denotes atomic masses of parent nuclei and daughter nuclei respectively. Q – value for ${\mathrm{\beta }}^{-}$ decay is Q₁ and ${\mathrm{\beta }}^{+}$ decay is Q₂. If me denotes mass of an electron Then correct statement in the following is (Q value is energy released in that reaction)

In case of ${\beta }^{-}$ decay

${}_{Z}X^A\to {}_{Z+1}Y^A+{}_{-1}e^0+\overline{\nu }+Q_1$

$Q_1=\left\{M_{nucleus}\left({}_{Z}X^A\right)-M_{nucleus}\left({}_{Z+1}Y^A\right)-m_e\right\}{c}^2$

$Q_1=\left[M_{nucleus}\left({}_{Z}X^A\right)+Z{m}_e\right]c^2$

        $-\left[M_{nucleus}\left({}_{Z+1}Y^A\right)-(Z+1)m_e\right]c^2$

$Q_1=\left[M_{atom}\left({}_{Z}X^A\right)-M_{atom}\left({}_{Z+1}Y^A\right)\right]c^2$

$\mathrm{For} {\mathrm{\beta }}^{+}\mathrm{decay}$

${}_{Z}X^A\to \to {}_{Z-1}Y^A+{}_{1}e^0+\nu +Q_2$

$Q_2=\left[M_{nucleus}\left({}_{Z}X^A\right)-M_{nucleus}\left({}_{z-1}Y^A\right)-m_e\right]c^2$

${Q}_2=\left\{M_{nucleus}\left({}_{Z}X^A\right)+Z{m}_e\right\}{c}^2-$

$\left[\left\{M_{nucleus}\left({}_{Z-1}Y^A\right)-\left(Z-1\right)m_e\right\}-2m_e\right]c^2$

$Q_2=\left[M_{atom}\left({}_Z{X}^A\right)-M_{atom}\left({}_{Z-1}Y^A\right)-2m_e\right]c^2$