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In a reaction, $A B (g) \underset{}{⇌} A (g) + B (g)$ the value of $K_{p}$ is numerically equal to 1/3^rd of total equilibrium pressure. What is the percentage dissociation of AB?

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80%

30%

45%

50%

answer is D.

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Detailed Solution

$α = \sqrt{\frac{k p}{k p + p}} = \sqrt{\frac{\frac{p}{3}}{\frac{p}{3} + p}}$

$= \sqrt{\frac{p / 3}{4 p / 3}} = 1 / 2 = 0.5 = 50 %$

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