In a reaction 2A+B→A2B, the reactant 'A' will disappear at

Given chemical reaction is 2 A + B → A 2 B Rate = - 1 2 d A dt = - d B dt = - - A 2 B dt d A dt = - 2 d B d t

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In a reaction $2 A + B \to A_{2} B, the reactant' A' will disappear at$

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Twice the rate at which B disappears

The same rate at which B disappears

Half the rate at which B disappears

answer is D.

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Given chemical reaction is

$2 A + B \to A_{2} B$

$Rate = - \frac{1}{2} \frac{d [A]}{dt} = \frac{- d [B]}{dt} = - \frac{- [A_{2} B]}{dt}$ $\frac{d (A)}{dt} = - 2 \frac{d (B)}{d t}$

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