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Q.

In a reacton $S O_{2 (g)} + N O_{2 (g)} ⇄ S O_{3 (g)} + N O_{(g)}$ ; $K c = 16$ If initially one mole each of all the four gases are taken in one litre vessel. The equilibrium concentrations of NO and NO₂ are respectively (in mole L^-1)

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a

1.6 & 0.4

b

0.4 & 0.4

c

1.6 & 1.6

d

0.4 & 1.6

answer is A.

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Detailed Solution

$\underset{1 - x}{\underset{1}{S O_{2 (g)}}} + \underset{1 - x}{\underset{1}{N O_{2 (g)}}} ⇄ \underset{1 + x}{\underset{1}{S O_{3 (g)}}} + \underset{1 + x}{\underset{1}{N O_{(g)}}}$
$\begin{aligned} 16 = \frac{(1 + x) (1 + x)}{(1 - x) (1 - x)} \Rightarrow x = \frac{3}{5} \\ ∴ [N o] = 1 + x = 1 + \frac{3}{5} = \frac{8}{5} = 1.6 \end{aligned}$

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