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Q.

In  a region of space the force on a electron is F=Cxj^, where C is a positive constant. The electron moves around a square loop in the xy-plane. Calculate the work done on the electron by the force F during a counterclockwise trip around the square. Is this force conservation or non conservative?

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a

CL2, Conservative

b

CL22, Non conservative

c

CL2, Non conservative

d

CL24, Non conservative

answer is C.

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Detailed Solution

IDENTIFY and SET UP: The force F is not constant, and in general it is not in the same direction as the displacement. To calculate the work done by F. we'll use the general expression for work, Eq.(6.14): W=p1p2F.dl

where dl is an infinitesimal displacement. We'll calculate the work done on each leg of the square separately, and add the result to find the work done on the round trip. If this round-trip work is zero, force F is conservative and can be represented by a potential energy function.

EXECUTE: On the first leg, from 0,0 to L,0, the force is every where perpendicular to the displacement. So F.dl=0,and the work done on the first leg is W1=0 .The force has the same value F=CLj^ everywhere on the second leg, from L,0 to L,L. The displacement on this leg is in the +y-direction, so dl^=dyj^ and  F.dl=CLj.dyj^=CLdy

The work done on the second leg is then W2=(L,0)(L,L)F.dl=Y=0y=LCL dy=CL0Ldy=CL2

On third leg, from L,L  to 0,L.F is again perpendicular to the displacement and so W4=0. The work done by F on the round trip is therefore W=W1+W2+W3+W4=0+CL2+0+0=CL2

The starting and ending points are the same but the total work done by F is not zero. This is a non conservative force; it cannot be represented by a potential-energy functions.

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