Q.

In a resonance tube experiment, the first two resonances are observed at length 10.5 crn and 29.5 cm. The third resonance is observed at the length __(cm).
 

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a

48.5

b

82.8

c

58.5

d

47.5 

answer is C.

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Detailed Solution

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λ2 = l2-l1 = 29.5-10.5 = 19 cm

Third resonance will be observed at

l3 = l2+λ2 = 29.5 + 19 = 48.5 cm

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