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Q.

In a reverse biased diode, when the applied voltage changes by 2V, the current is found to change by 0.25μA. The reverse bias resistance of the diode is

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a

$2 \times 10^{6} Ω$

b

$8 \times 10^{5} Ω$

c

$8000 Ω$

d

$8 \times 10^{6} Ω$

answer is D.

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Detailed Solution

$D y n a m i c R e s i s \tan c e : R = \frac{Δ V}{Δ I} = \frac{2}{0.25 \times 10^{- 6}} = 8 \times 10^{6} Ω$

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