In a rhombus PQRS, if PQ = QR = RS = PS = 5 cm, and the diagonal PR = 8 cm and SQ = 6 cm, then which one of the following relations is correct?

We know that the diagonals of a rhombus bisect each other at a right angle.

$\therefore \mathrm{OP}=\mathrm{OR}=\frac{\mathrm{PR}}{2}=\frac{8}{2}=4 \mathrm{cm}$

and $\mathrm{OS}=\mathrm{OQ}=\frac{\mathrm{SQ}}{2}=\frac{6}{2}=3 \mathrm{cm}$

Now in $△\mathrm{OPS},$

$\mathrm{OP}>\mathrm{OS}$

We know that in a triangle, the angle opposite to the longer side is larger.

Therefore, $\mathbf{\angle }\mathbf{PSO}\mathbf{>}\mathbf{\angle }\mathbf{SPO}$