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In a rigid container NH₃ is kept at certain temperature, if on doubling the temperature it is completely dissociated into N₂ and H₂. Find final pressure to initial pressure ratio :

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Detailed Solution

${2NH}_{3} ⇌ N_{2} + 3 H_{2} PV=nRT [V and R const.] \frac{P_{1}}{P_{2}} = \frac{n_{1} T_{1}}{n_{2} T_{2}} = \frac{2 \times T}{4 \times 2 T} = \frac{1}{4} \frac{P_{2}}{P_{1}} = 4$

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